Infosys  Placement Paper   Aptitude - Puzzle   Hyderabad-10 Sep 2006

#### Infosys  Placement Paper   Aptitude - Puzzle   Hyderabad-10 Sep 2006

• Posted by  FreshersWorld
7 Jan, 2012

infosys placement paper on 10th September  at hydrabad

hi frends,
here are the questions

1. (X)^1/3 -  (X)1^9=60
approach let (X)^1/3 =t
so  t-(t)^1/3=60
so now hit and trial
the number which satisfies it is 64
so t=64
so (X)^(1/3)=64

2.A cube problem which is painted with red  is cut into 27 small cubes with six straight cuts
a) how many cubes are there with 0 side red colour
b) how many cubes are there with 1 side red colour
c) how many cubes are there with 2 side red colour
d) how many cubes are there with 3 side red colour

A
0 faces coloured-1(27-(12+6+8))
1 faces coloured-6(All middle ones are 1 face colored red  1*6=6)
2 faces coloured-12(exclude corners other are 2 faces colored red so 4*3=12)
3 faces coloured-8( all corners are 3 faces colored red so 2 at front and 2 at back)

Approach draw a cube and cut it into 6 parts

3.A man starts from XYZ city and drives a constant speed. After some time he sees a milestone with two digits written on it.after he drives for an hour, he sees another milestone with the same digits, but in reversed order. After another hour ofjourney, he sees another milestone with original digits but with a zero between them.Find the speed of the car?

A let the distance showed on first milestone be 10x+y
distance showed on second milestone be 10y+x
now hit and trial
let x=1 y=6  so 16 ,61,106   distance is 45km/hr.
this is the only condition satisfies

4.A five digit no whose third digit is one greater than the sum of the first two digits and the third digit is double the fourth digit and fourth digit is double the fifth digit and second digit is greater than first digit by 5. and if we multiply fourth and fifth digith we get third digit.
A
Let the digits be denoted by p1p2p3p4p5
p3=p1+p2+1
p3=2p4
p4=2p5
p2=p1+5
hit and trial
16842

5. There was a cycle race going on. 1/5th of the those in front of a person and 5/6th of those behind him gives the total
number of  participants. How many people took part in the race?

A. Let total number of people be x
1/5(x-1)+5/6(x-1)=x
so x=31

6. .B and C initially speak English but when D joined Spanish they too took up Spanish. The only common language between A, B and E is French. The only common language between C and E is Italian. Three people speak Portuguese. Most common language is Spanish. One person knows all the 5 language, one person knows 4 languages, one person knows 3 languages, one person knows 2 languages and one person knows only one language.

A -French, Spanish, Portuguese

B -English, Spanish, French, Portuguese, Italian

C - English, Spanish, Italian, Portuguese

D -Spanish

Approach draw table and solve it u will get it

7.Uncle Reuben and aunt Cynthia came to town to shop.Reuben bought a suit and hat for \$15.Cynthia paid as much as for her hat as Reuben did for his suit.Then she spent the rest of her money for her dress.On the way to home Cynthia called Reubens attention to the fact that his hat cost \$1 more than her dress.Then uncle said if we had divided our hat money differently such that we bought a different hats mine costing 1 and ½ times cost of yours then we would have spent the equal amount of money.

(i)How much the hat would cost in that case?

(ii)What is the total amount spent?

A i dont know the approach

8.  There was a match to be held.And 100 nations were to participate in that match.It was totally an elimination match,that is if a team loses a match it must be eliminated.Find out the total number of matches played to find out the grand winner?
A very easy 99 matches
just take example with 4teams
T1,T2,T3,T4
T1-T2    T1 won T2 eliminated
T1-T3    T3 won and T1 eliminated
T3-T4    T3 won and T4 eliminated
so if there are totally 4 teams 3 matches are required to determine the winner if there are 100 teams total 99 matches are required.

9.There were totally 100 men.85 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married?

A.  85 are married so 15 are not married
75 have TV           25 dont have TV
70 have AC           30 dont have AC

so totally  100-(15+25+15+30)=15 have all

10.One more question was some 11 names were given we have to find who is youngest
its a bit confusing draw the table and explain u will surely get the answer
English part is a bit easy and confusing also  please concentrate on it .