HP  Placement Paper   Whole Testpaper   BANGALORE-21 Oct 2003

HP  Placement Paper   Whole Testpaper   BANGALORE-21 Oct 2003

  • Posted by  FreshersWorld 
    7 Jan, 2012

     HP PAPER - 21 OCT 2003- BANGALORE

    I  attended the test conducted on 21st of oct at their office 29,Cunningham Road. There were 80 q's to be answered in 75mins unlike the previous ones.

    there were 3 sections
    PART- 1 --> 40 q's (Fundamental computer Concepts, includes OS,N/w , protocols)
    PART-2  --> 20 q's (Purely C ) --  bit tricky (involves ADA concepts)
    PART-3 -->  20 q's (Analytical) --- very easy

    I don't remeber all the q's.however some of them which i do have been written below. They r not in order or part of .

     Q : What is not a part of OS ?
     O :      swapper,compiler,device driver,file system.
     A : compiler.

     Q : what is the condition called when the CPU is busy swapping in and out pages of memory without doing any  useful work ?
     O :   Dining philosopher's problem,thrashing,racearound,option d
     A: thrashing.

     Q : How are the pages got into main memory from secondary memory? DMA, Interrupts,option3, option 4
      A : as far as i know its  Interrupts --by raising a page fault exception.

    Q : What is the use of Indexing ?
    O : fast linear access, fast random access, sorting of records  , option 4
    A : find out.

    Q : in terms of both space and time which sorting is effecient. (The question is rephrased .)
    O : merge sort, bubble sort, quick sort, option 4
    A :  find out

    which case statement will be executed in the following  code ?
      int i =1;
             case 1 : printf ("");
             case 2 : printf("");
             default : printf("");

    Answer : Case1 will only be executed.

    Q : In the given structure  how do you initialize the day feild?
          struct time {
              char  * day ;
             int     * mon ;
             int     * year ;
              } * times;

    Options : *(times).day, *(times->day), *times->*day.

    Answer : *(times->day) -- after the execution of this statement  compiler generates   
                  error.i didn't understand why.can anybody explain.

    Q: The char has 1 byte boundary , short has 2 byte boundary, int has 4 byte boundary.
         what is the total no: of bytes consumed by the following structure:
       struct st {
       char a ;
       char b;
       short c ;
       int z[2] ;
       char d ;
       short f;
       int q ;

    Options are given.
    Answer : its very easy 20 and not 19 .

    Apart from these there were other q's concerning minimal spanning tree, shortest path and some complexity questions.

    (Paper Submitted By : Arun)

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