CTS  Placement Paper   General - Other   -

#### CTS  Placement Paper   General - Other   -

• Posted by  FreshersWorld
7 Jan, 2012

COGNIZANT (CTS)

There wer  5 section  8 questions each (40 q totally) 60 minute 5 different sets of question papers 1 Mark each

0.25 negative marking

# CTS BLACK

Vocabulary, strings, dominoes, functions, coding (each section 8 ques)

# CTS BROWN

Word series, numerical series, functions, figures, verbal (each section 8 ques)

# CTS VIOLET

Functions, strings, bricks, jigsaw puzzle, cryptic clues (each section 8 ques)

# CTS RED

1) 8 functions              2) 4 cryptic clues, 4 anagrams

3) 4 Tetris figures, 4 bricks   4) 8 strings                     5) 4 jigsaw puzzles 4 number series

# BROWN 2002

There were different papers for different sessions.The paper had 5 sections, 5 * 8 = 40 Que's. totally

Section 1: Functions

# Q: 1 - 8

Certain functions were given & based upon the rules & the choices had to be made based on recursion. This is time consuming, but u can do it. Try to do it at the end. Start from the last section.

L(x) is a function defined. functions can be defined as

L(x)=(a,b,ab) or (a,b,(a,b),(a,(b,b)),a,(b,b)).... two functions were given A(x) & B(x) like

if l(x)=(a,b,c) then A(x)=(a) & B(x)=(b,c)

i.e., A(x) contains the first element of the function only.&   B(x) contains the remaining, except the first element.

then  the other two functions were defined as

C(x) =  *   if L(x) = ()

A(x)  if L(x) = () & B(x) != ()  & C(B(x))  otherwise

D(x) =  *            if L(x) = ()

**             if B(x) = ()

A(x), if L(x) != () & B(x) != ()

D(D(x)),otherwise ;

Now the Questions are,

1 : if L(x) = (a,b,(a,b))  then C(x) is ?

(a): a  (b): b   (c): c   (d): none

2 : if L(x) = (a,b,(a,b)) then find D(x)

same options as above

3 : if L(x) = (a,b,(a,b),(b,(b)))  find C(x)

4 :   find D(x)

5 : if L(x) = (a,(a,b),(a,b,(a,(b))),b)  then find c(x)

6 :   find D(x)

7 : if L(x) = (a,b,(a,b)) then find C(D(x))

8 :   find D(C(x))

Section 2: Word series

# Q?s: 9 - 16

If S is a string then p, q, r forms the sub strings of S. For eg, if S = aaababc & p = aa,q = ab, r =bc . Then on applying p à q on S is that ababaabc. Only the first occurrence of S has to be substituted. If there is no sub string of p, q, r on s then it should not be substituted.If S = aabbcc, R = ab, Q = bc. Now we define an operator R &#61672;

Q when operated on S, R is replaced by Q, provided Q is a subset of S, otherwise R will be unchanged. Given a set S =? when R&#61672; Q, P&#61 = 672; R, Q &#61672; P operated successively on S, what will be new S? There will be 4 =: if s = aaababc & p = aa, q = ab, r = bc then applying p à q, q à r & r à p will give,

(a): aaababc  (b): abaabbc  (c): abcbaac   (d): none of the a,b,c

10: if s = aaababc & p = aa q = ab r = bc then applying q à r & r à p will give,

11: if s = abababc & p = aa q = ab r = bc then applying p à q, q à r & r à p will give,

12: if s = abababc & p = aa q = ab r =bc then applying q à r & r à p will give,

13: if s=aabc  & p=aa q=ab r=ac then applying p->q(2) q->r(2) r->p  will give,(2) Means applying the same thing

twice.

14: Similar type of problem.

15) if s = abbabc p = ab q = bb r = bc then to get s = abbabc which one should be applied.

(a): p->q,q->r,r->p

16) if s = abbabc p = ab q = bb r = bc then to get s = bbbcbabc which one should be applied.

Let us consider a set of strings such as S = aabcab. We now consider two more sets P and Q that also contain strings. An operation Pà Q is defined in such a manner that if P is a subset of S, then P is to be replaced by Q. In the following questions, you are given various sets of strings on which you have to perform certain operations as defined above. Choose the correct alternative as your answer.(Below are some ques from old ques papers)

a) Let S = abcabc, P = bc, Q = bb and R = ba. Then P à Q, Q à R and R à P, changes S to

________?         (A) ............  (B) abcabc         (C) ............  (D) none of A, B, C

b) Let S = aabbcc, P = ab, Q = bc and R = cc. Then P à Q, Q à R and R à P, changes S to

_________?        (A) ababab        (B) ............   (C) ............  (D) none of A, B, C

c) Let S = bcacbc, P = ac, Q = ca and R = ba. Then P à Q, Q à R, P à R and changes S to

________?         (A) ............  (B) ............   (C) bcbabc     (D) none of A,B,C

d) Let S = caabcb, P = aa, Q = ca and R = bcb. Then P à Q, P à R, R àQ and changes S to

________?

(A) ............  (B) ............   (C) ............  (D) none of A,B,C

## Section 3: numerical series

17:   2,20,80,100?

(a): 121,  (b): 116  (c):    (d):none

18:   10,16,2146,2218?